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100x^2-4639.36x-6326.4=0
a = 100; b = -4639.36; c = -6326.4;
Δ = b2-4ac
Δ = -4639.362-4·100·(-6326.4)
Δ = 24054221.2096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4639.36)-\sqrt{24054221.2096}}{2*100}=\frac{4639.36-\sqrt{24054221.2096}}{200} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4639.36)+\sqrt{24054221.2096}}{2*100}=\frac{4639.36+\sqrt{24054221.2096}}{200} $
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